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Old 02-18-2011 | 11:11 PM
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You know you love math

Car A is traveling at a constant speed.

Assume it takes Car B 30 seconds to get up to speed (since it was, you know, very well hidden off the side of a road between bushes)

Car B catches up with Car A in 3.5 miles after Car B reaches it's final and constant speed.


Identify the potential speed Car B was travelling at, base on practical assumpsions for Car A on a two-lane highway.

---
Now repeat excercise, and assume Car B took only 20 seconds to get up to speed.
Old 02-18-2011 | 11:18 PM
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Too damn fast... 420mph for 30 secs
and 630 mph for 20 secs.

Edit Nvm I read wrong. Thats 30 and 20 seconds of constant speed...
Old 02-18-2011 | 11:19 PM
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um...this is dumb...why would you start a thread like this...
Old 02-18-2011 | 11:22 PM
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Do you need physics/calculus help?
Old 02-18-2011 | 11:22 PM
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Originally Posted by breftayka
Too damn fast... 420mph for 30 secs
and 630 mph for 20 secs.

Edit Nvm I read wrong. Thats 30 and 20 seconds of constant speed...

You're way off, sir . . .
Old 02-18-2011 | 11:35 PM
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Originally Posted by nethole
You're way off, sir . . .
So? I was in a jet, and that's how fast I was going...
Physics sucks *****...
Old 02-19-2011 | 12:25 AM
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Omg .. Physics!
Old 02-19-2011 | 12:53 AM
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omg fack physics, the last time was when i took it in college.. never again! lol
Old 02-19-2011 | 01:11 AM
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this question doesnt have anything to do with physics hahaha unless you bring masses and forces into it (acceleration is already present but no parameters are given to solve the acceleration)......F=ma

there are an infinite number of solutions because you have not given enough initial conditions to solve the problem

a singularity function might be necessary to solve this without more info

unless i am really drunk (which i am a little) and am missing something lol

30(a) + 3.5x - x(y) = y

yeah im too drunk to think about this lol
Old 02-19-2011 | 07:15 AM
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Originally Posted by nethole
Car A is traveling at a constant speed.

Assume it takes Car B 30 seconds to get up to speed (since it was, you know, very well hidden off the side of a road between bushes)

Car B catches up with Car A in 3.5 miles after Car B reaches it's final and constant speed.


Identify the potential speed Car B was travelling at, base on practical assumpsions for Car A on a two-lane highway.

---
Now repeat excercise, and assume Car B took only 20 seconds to get up to speed.
Sorry, got distracted by your signature... so... ticket came first. That little son of...
Old 02-19-2011 | 07:56 AM
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There are way too many unknowns in your original problem. For example, the rate of acceleration of car B before getting up to speed, which would help determine where it was at after 30 seconds (we know that car A was 0.67 miles further down the road after 30 seconds).

But, my assumption is that A is traveling at 80 mph, which means it's covering 1.33 miles per minute. So it takes it 2.625 minutes to travel 3.5 miles. So assuming car B doesn't start the pursuit until 30 seconds after car A passes, then it would have to cover 4.167 miles in 2.625 minutes (since car A would have traveled 0.67 miles in 30 seconds). This ends up being roughly 95.25 mph.

If car B waiting only 20 seconds, it would only have to travel at 90.16 mph to catch up.

Of course, I'm making assumptions that don't fall in line with your original question (like instantaneous acceleration), but then again, the original questions doesn't make *perfect* sense, because why would car B be pursuing car A at a constant speed? Most "car Bs" continue accelerating until they catch "car A" or until their speed is considered unsafe (which is likely higher than 95mph).
Old 02-19-2011 | 08:02 AM
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Originally Posted by nethole
Car A is traveling at a constant speed.

Assume it takes Car B 30 seconds to get up to speed (since it was, you know, very well hidden off the side of a road between bushes)

Car B catches up with Car A in 3.5 miles after Car B reaches it's final and constant speed.


Identify the potential speed Car B was travelling at, base on practical assumpsions for Car A on a two-lane highway.

---
Now repeat excercise, and assume Car B took only 20 seconds to get up to speed.
You must be kidding. Even a math doofus would understand that this is a huge waste of time without being given values.
Old 02-19-2011 | 08:05 AM
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Just because you don't want to follow the original assumptions, doesn't mean it can't be done [credit where credit is due, I believe my wife wrote that on one of her student's papers the last time one of the snowflakes thought they were too special to follow directions]. Not every problem has a closed form solution.

The asumptions given simplify what you'd need to do to provided bounds to the answer for this problem.

Multivariable Optimization is your friend, when it comes to engineering....

And when you need to quickly provide an estimate to a problem with multiple unknowns.






Originally Posted by VaTech03
There are way too many unknowns in your original problem. For example, the rate of acceleration of car B before getting up to speed, which would help determine where it was at after 30 seconds (we know that car A was 0.67 miles further down the road after 30 seconds).

But, my assumption is that A is traveling at 80 mph, which means it's covering 1.33 miles per minute. So it takes it 2.625 minutes to travel 3.5 miles. So assuming car B doesn't start the pursuit until 30 seconds after car A passes, then it would have to cover 4.167 miles in 2.625 minutes (since car A would have traveled 0.67 miles in 30 seconds). This ends up being roughly 95.25 mph.

If car B waiting only 20 seconds, it would only have to travel at 90.16 mph to catch up.

Of course, I'm making assumptions that don't fall in line with your original question (like instantaneous acceleration), but then again, the original questions doesn't make *perfect* sense, because why would car B be pursuing car A at a constant speed? Most "car Bs" continue accelerating until they catch "car A" or until their speed is considered unsafe (which is likely higher than 95mph).
Try going 95 mph on a two lane road . . .
Old 02-19-2011 | 08:06 AM
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Multi-variable analaysis, How does it work?

Originally Posted by MSCA
You must be kidding. Even a math doofus would understand that this is a huge waste of time without being given values.
Like Magnets, but different . . .
Old 02-19-2011 | 08:15 AM
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So how many mph over did they nail you at??


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